Test Preparation on IIT JEE Mains Mock Test-3&4

In sucrose, glucose and fructose are linked to each
other by covalent linkage.
Cellobiose is a disaccharide, it consists of two
glucose molecules linked by a β(1→4)
bond. Maltose also known as maltobiose or malt
sugar, is a disaccharide formed from two units
of glucose joined with an α(1→4) bond. Lactose is
a disaccharide sugar that is found most notably in
cow milk and is formed from linkage of galactose
and glucose.

Camphor can undergo sublimation where as
caffine cannot so it can be separated from the
mixture by sublimation.

The amino group of an aryl amine may be replaced
by a ‘H’ upon reaction of its diazonium salt wi th
H3PO2.

For the preparation of iodoform, a compound
containing CH3CO- group, a base and iodine is
needed.
C6H5COCH3 + 3I2 + 3NaOH _
C6H5COONa + CHI3 + 3NaI + H2O

Aldehydes give silver mirror test with Tollen’s
reagent which is [Ag(NH3)2]+

Inert pair effect is shown by Tl.

Nesseler’s reagent is K2[HgI4]

The IUPAC name of Na3[Co(NO2)6] is Sodium
hexanitrocobaltate(III)

Ziegler–Natta catalysts are used to polymerize
terminal 1-alkenes. These consist of transition 

metal catalyst, like TiCl3 and Al(C2H5)2Cl, or
TiCl4 with Al(C2H5)3.

P4O6 reacts with water to form phosphorous acid
(H3PO3)P4O6 + 6H2O _ 4H3PO3

More energy is required to remove an electron
from the completely filled or half filled subshells
and also from the orbitals which are closer to the
nucleus.

The number and types of bonds between two
carbon atoms in CaC2 are one sigma and two pi(p).

S2O7.2- has no S-S bond.

1.5N H2O2 contains 17 x1.5 = 25.5 g of H2O2
According to the following equation,
2H2O2 _ 2H2O + O2
2x34 g 22.4L
68 g of H2O2 = 22.4L of O2
25.5 g of H2O2 =
= 8.4 L
Volume strength of H2O2 is expressed as the
volume of O2 that a solution of H2O2 gives on
decomposition by heat. Since 1.5 N H2O2 solution
gives 8.4L of oxygen at STP so its volume strength
is 8.4.

When gold is dissolved in aqua regia, HAuCl4
(chloroauric acid) is formed.
Au (s) + 3NO3
-(aq) + 6 H+ (aq) → Au3+(aq) +
3 NO2(g) + 3 H2O(l)

NaHCO3 acts as an antacid.

Straight chain hydrocarbons have higher boiling
point than branched chain hydrocarbons. Higher
hydrocarobons have higher boiling point than
lower hydrocarbons

Straight chain hydrocarbons have higher boiling
point than branched chain hydrocarbons. Higher
hydrocarobons have higher boiling point than.lower hydrocarbons