Rotational Motion-I Physics Test Series IIT JEE

Test Preparation on Rotational Motion-I- Physics Test Series IIT JEE-2020

1.

The distance between the carbon atom and the oxygen
atom in a carbon monoxide molecule is 1.1 Å. Given, mass
of carbon atom is 12 a.m.u. and mass of oxygen atom is 16
a.m.u., calculate the position of the center of mass of the
carbon monoxide molecule

16.3 Å from the carbon atom
21 Å from the oxygen atom
30.63 Å from the carbon atom
40.12 Å from the oxygen atom

2.

11
22
33
44

3.

11
22
33
44

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