1.
All the boys of class XI D passed the annual examination but a few girls failed. If all the boys to girls as 5:1, what would be the number of girls who failed in class XI D?
Total number of boys in XI D = 40 Number of girls in XI D = 25% of 40 = 10 Since all the boys of XI D passed, so the number of boys in XII D = 40 Ratio of boys & girls in XII D is 5: 1 Number of girls in XII D = 1/5
2.
What should be the total number of students in the school if all the boys of class XI A together with all the girls of Class XI B and Class XI C were equal to 25% of the total number of students?
Number of boys in XI A = 44 Number of girls in XI B = 25% of 48 = 12 Number of girls in XI C = 25% of 48 = 12 (44 + 12 + 12) = 68 Let x be the total number of students. Then 25% of x = 68 Or, x = (68
3.
Boys of which of the following classes need to be combined to equal four times the number of girls in class XI B and class XI C were to be equal to 25% of the total number of students?
4 times the number of girls in XI B & XI C = 4 (12 + 12) = 96.
4.
If boys of class XI E participating in chess together with girls of class XI B and class XI C participating in Table Tennis & Hockey respectively are selected for a course at the college of sports, what percent of the students will get this advantage approximately?
Number of boys in XI E = 4 Number of girls in XI B playing Table tennis = 25% of 16 = 4 Number of girls in XI C playing Hockey = 25% of 8 = 2 (4 + 4 + 2) = 10 Total number of students (228 + 25% of 228) = 285 Let x% of 285 = 10 Or, x = (10
5.
If for social work every boy of class XI D and class XI C is paired with a girl of the same class, what percentage of the boys of these two classes cannot participate in social work?
Since the number of girls = 25% of the number of boys, so only 25% of the boys can participate in social work
