RS Aggarwal Solutions Class 9 Maths Chapter 17 Bar Graph Histogram and Frequency Polygon (Updated For 2023)

RS Aggarwal Solutions Class 9 Maths Chapter 17 Bar Graph Histogram and Frequency Polygon: If you think Class 9 Maths is tricky, start studying RS Aggarwal Solutions Class 9 Maths. It can help you clear your doubts as the RS Aggarwal Solutions Class 9 Maths Chapter 17 Bar Graph Histogram and Frequency Polygon are very credible and well-explained. Ace your Class 9 Exams with the RS Aggarwal Solutions Class 9 Maths Chapter 17.

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RS Aggarwal Solutions Class 9 Maths Chapter 17 Bar Graph Histogram and Frequency Polygon

RS Aggarwal Solutions Class 9 Maths Chapter 17 Bar Graph Histogram and Frequency Polygon – Overview

• Bar Graph

1. It portrays the comparison between two discrete measured values.
2. The bar graph is a representation of the axis, showing a comparison between two different categories of values and represented through uniform width bars placed with the axis at an equal spacing to portray certain variables.
3. The variable is depicted on the base axis, and the height of the bar represents the value.

• Histogram 

1. It is a form of representation of specific data used in the case of continuous class intervals.
2. A histogram is similar to bar charts and simply represents figures identical to rectangles, with areas equal to the frequency of the given variables and width similar to the class intervals.

• Constructing A Histogram

1. Start by constructing a horizontal line to denote the classes.
2. Then, draw even marks on the line corresponding to the class.
3. Then, label the marks and name the horizontal axis to prevent any confusion later.
4. After that, construct a vertical line ending at the lowest class.

5. Again label and name the line.

6. Then, draw a rectangle on the baseline of heights equal to the frequency of the class.

• Frequency Polygon

1. It is a particular type of graph used to represent a specific set of data visually.
2. It is drawn by optimizing the data and joining each class interval’s midpoints with a line. The heights of these lines highlight the frequencies of the class.
3. To calculate the midpoints more precisely, you must add the upper and lower limits of the intervals’ boundary values and then divide them by 2.

The midpoint of the polygon =  (Upper limit + Lower limit)/2

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