RS Aggarwal Solutions Class 9 Maths Chapter 14 Areas of Triangles and Quadrilaterals: Be it your Class 9 Maths assignments or tests, RS Aggarwal Solutions Class 9 Maths got your back. You can easily understand the solutions of RS Aggarwal Solutions Class 9 Maths Chapter 14 Areas of Triangles and Quadrilaterals and they are as per the current CBSE Syllabus, thanks to the subject matter experts.
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RS Aggarwal Solutions Class 9 Maths Chapter 14 Areas of Triangles and Quadrilaterals
RS Aggarwal Solutions Class 9 Maths for Chapter 14 Areas of Triangles and Quadrilaterals – Overview
In Chapter 14 of RS Aggarwal Solutions Class 9 Maths, you will get to know about the following topics:
- Area of different triangles and quadrilaterals
- Area of quadrilaterals using diagonals
In this chapter, you will have to deal with two exercises:
- There are 44 questions in the first exercise that covers various concepts of finding the area of triangles and different quadrilateral figures using suitable formulae.
- In the second exercise, there are various objective-type questions based on the concepts you have learned in the previous exercise.
- Important Formulae
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The basic area of any triangle: ½ × b × h
where b is the base and h is the height of the triangle
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Area of an equilateral triangle: An equilateral triangle is a triangle whose all sides are equal.
Area of an equilateral triangle = √3/4 × a²
Height of an equilateral triangle = √3/4 × a
where a is the measure of its sides.
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Area of an isosceles triangle: b/4 x √4a²-b²
where a is the measure of the two equal sides and b is the measure of the base.
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Area of a triangle having three different sides (Heron’s formula):-
Suppose a triangle has sides measuring a, b, and c.
According to Heron’s formula:-
The first step includes finding the semi-perimeter of the triangle:
Semi-perimeter (S) = (a+b+c)
Using the above finding and implementing it in Heron’s formula for the area of a triangle constitutes the second step.
Area = √ s (s-a) (s-b) (s-c)
There are seven different types of quadrilaterals, each having a specific formula for its area.
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Parallelogram: Its opposite sides are equal and parallel to each other.
Area of a parallelogram = base × height
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Rectangle: It is a parallelogram with all four angles measuring 90⁰
Area of a rectangle = length × breadth
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Square: It is a rectangle whose all sides are equal
Area of a square = side²
-
Rhombus: It is a parallelogram whose all sides are equal.
Area of a rhombus = base × height
Area of rhombus using diagonals = (d1xd2)/2
-
Trapezium: A trapezium has one pair of sides parallel.
Area of trapezium = 1/2 x (a + b) × h
where a and b are the measure of two parallel-sided and h is the height
-
Kite: It has two pairs of equal adjacent sides but unequal opposite sides.
Area of a kite = (d1xd2)/2
NOTE: The perimeter of any figure is equal to the sum of all its sides.
This is the complete blog on the RS Aggarwal Solutions Class 9 Maths for Chapter 14 Areas of Triangles and Quadrilaterals. To know more about the CBSE Class 9 Maths exam, ask in the comments.
FAQs on RS Aggarwal Solutions Class 9 Maths Chapter 14 Areas of Triangles and Quadrilaterals
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Is the RS Aggarwal Solutions Class 9 Maths Chapter 14 a credible source for Class 9 Maths exam preparation?
Yes, the solutions are prepared by the subject matter experts, hence credible.
How many questions exist in RS Aggarwal Solutions Class 9 Maths Chapter 14 Ex 14.1?
There are 44 questions in this exercise.
How many exercises are there in RS Aggarwal Solutions Class 9 Maths Chapter 14 Areas of Triangles and Quadrilaterals?
There are 2 exercises in this chapter.