RS Aggarwal Solutions Class 7 Maths Chapter 5 Ex 5.2 (Updated For 2021-22)

RS Aggarwal Solutions Class 7 Maths Chapter 5 Ex 5.2

RS Aggarwal Solutions Class 7 Maths Chapter 5 Ex 5.2: If you are looking for a good help guide for your Class 7 Maths exam prep, we recommend you RS Aggarwal Solutions Class 7 Maths. All the solutions of RS Aggarwal Solutions Class 7 Maths Chapter 5 Ex 5.2 are well-explained, accuarte and as per the current CBSE Syllabus. You can even access the PDF of the guide offline.

Download the Free PDF of RS Aggarwal Solutions Class 7 Maths Chapter 5 Ex 5.2 using the download link given in the blog. To know more, read the whole blog.

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RS Aggarwal Solutions Class 7 Maths Chapter 5 Ex 5.2

 


RS Aggarwal Solutions Class 7 Maths Chapter 5 Ex 5.2 – Overview

Introduction

  • In exponents, we multiply the same number following the number of times. Eg: we can write, 24 = 2 x 2 x 2 x 2. It means that the number ‘2’ is multiplied four times. Therefore, the term exponent refers to raising the number for a power, where we consider the exponent as the power.
  • The number to which the power is raised is called a base of the power. In the example, we gave above in “24”, “2” is the base value and “4” is the exponent value.  

Law Of Exponents Formulae

Considering p and q as two non-zero rational numbers, as well as, m and n as two natural numbers. Accordingly to this, the law of exponents in the following ways:
  1. pm x pn = pm + n
  2. (pm) n = pmn
  3. pmpn = pm – n, here,  m > n
  4. pmpn = 1 / pn – m, here,  n > m
  5. (pq) m = pm qm

This is the complete blog on RS Aggarwal Solutions Class 7 Maths Chapter 5 Ex 5.2. To know more about the CBSE Class 7 Maths exam, ask in the comments.

FAQs on RS Aggarwal Solutions Class 7 Maths Chapter 5 Ex 5.2

Define Power Of The Base.

The number to which the power is raised is called a base of the power. In the example, we gave above in “24”, “2” is the base value and “4” is the exponent value.  

What are the important formulae in this exercise?

pm x pn = pm + n
(pm) n = pmn
pmpn = pm – n, here,  m > n
pmpn = 1 / pn – m, here,  n > m
(pq) m = pm qm, where p and q as two non-zero rational numbers, as well as, m and n as two natural numbers.

From where can I find the download link for the RS Aggarwal Solutions Class 7 Maths Chapter 5 Exercise 5.2 PDF?

You can find the download link in the above blog.

How much does it cost to download the RS Aggarwal Solutions Class 7 Maths Chapter 5 Ex 5.2 PDF?

You can download it for free.

Can I access the RS Aggarwal Solutions Class 7 Maths Chapter 5 Exercise 5.2 PDF Offline?

Once you have downloaded the PDF online, you can access it offline whenever you want.

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