RS Aggarwal Solutions Class 10 Maths Chapter 11 Ex 11.1 (Updated For 2024)

RS Aggarwal Solutions Class 10 Maths Chapter 11 Ex 11.1: Class 10 Maths can be quite tricky for some students and to help you with that we have the RS Aggarwal Solutions Class 10 Maths. You can easily understand the solutions of RS Aggarwal Solutions Class 10 Maths Chapter 11 Ex 11.1 as they are written by subject matter experts. 

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RS Aggarwal Solutions Class 10 Maths Chapter 11 Ex 11.1

Access RS Aggarwal Solutions Class 10 Maths Chapter 11 Ex 11.1

Question 1.
Solution:
On substituting the value of various T-ratios, we get
sin60° cos30° + cos60° sin30°

Question 2.
Solution:
On substituting the value of various T-ratios, we get
cos60° cos30° – sin60° sin30°

Question 3.
Solution:
On substituting the value of various Tratios, we get
cos45° cos30° + sin45° sin30°

Question 4.
Solution:
On substituting the value of various Tratios, we get

Question 5.
Solution:

Question 6.
Solution:
On substituting the value of various Tratios, we get

Question 7.
Solution:
On substituting the value of various Tratios, we get

Question 8.
Solution:
On substituting the value of various Tratios, we get

Question 9.
Solution:
On substituting the value of various Tratios, we get

Question 10.
Solution:
(i)

(ii)

Overview of RS Aggarwal Solutions Class 10 Maths Chapter 11 Ex 11.1

About Arithmetic Progression

The differences between every two consecutive terms in an Arithmetic Progression (AP) are the same. It is possible to derive a formula for the nth term from an Arithmetic Progression. The sequence 3, 6, 15, 21, 27,…, for example, is an Arithmetic Progression (AP) because each number is obtained by adding 3 to the previous term. The nth term in this sequence is 6n-3. By substituting n=1,2,3,… in the nth term, you can get the sequence’s terms. i.e.,

When n = 1, 6n-3 = 6(1)-3 = 6-3=3

When n = 2, 6n-3 = 6(2)-3 = 12-3=9

When n = 3, 6n-3 = 6(3)-3 = 18-3=15

What exactly is Arithmetic Progression?
An Arithmetic Progression (AP) can be defined in two ways:

An Arithmetic Progression is a series of terms with the same differences between them.

Each term is obtained by adding a fixed number to the previous term in an Arithmetic Progression, except the first.

Arithmetic Progression Terminology

First Term: The first term of an AP is the progression’s first number, as the name implies. It is usually denoted by the letters a1 (or) a.

For instance, the first term in the sequence 3,9,15,21,28,… is 3, i.e. a1=3 (or) a=3.

Common Difference: We know that an AP is a sequence in which each term, except the first, is obtained by multiplying the previous term by a fixed number. The “fixed number” is known as the “common difference,” and it is represented by the letter ‘d.’ If the first term is a1, then the second term is a1+d, the third term is a1+d+d = a1+2d, and so on. For instance, each term in the sequence 3,9,15,21,27… is obtained by adding 6 to the previous term, except the first term. As a result, d=6 is a common difference. The difference between every two consecutive terms of an AP is the most common. As a result, the formula for calculating an AP’s common difference is d = an-a{n-1}.

Calculating the Sum of Arithmetic Progression Formula

Consider an Arithmetic Progression (AP) with a1 (or) an as the first term and d as the common difference.

Sn = n/22a + (n−1)d
is the sum of the first n terms of an Arithmetic Progression when the nth term is unknown.

Sn = n/2a1 + an
is the sum of the first n terms of an Arithmetic Progression when the nth term, an, is known.

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