RD Sharma Class 12 Solutions Chapter 11 Exercise 11.4 (Updated for 2024)

Exercise 11.4 Page No: 11.74

Find dy/dx in each of the following:

1. xy = c²

Solution:

2. y³ – 3xy² = x³ + 3x²y

Solution:

Given y³ – 3xy² = x³ + 3x²y,

Now we have to find dy/dx of given equation, so by differentiating the equation on both sides with respect to x, we get,

3. x^2/3 + y^2/3 = a^2/3

Solution:

Given x^2/3 + y^2/3 = a^2/3,

Now we have to find dy/dx of given equation, so by differentiating the equation on both sides with respect to x, we get,

4. 4x + 3y = log (4x – 3y)

Solution:

Given 4x + 3y = log (4x – 3y),

Now we have to find dy/dx of it, so by differentiating the equation on both sides with respect to x, we get,

Solution:

6. x⁵ + y⁵ = 5xy

Solution:

Given x⁵ + y⁵ = 5xy

Now we have to find dy/dx of given equation, so by differentiating the equation on both sides with respect to x, we get,

7. (x + y)² = 2axy

Solution:

Given (x + y)² = 2axy

Now we have to find dy/dx of given equation, so by differentiating the equation on both sides with respect to x, we get,

8. (x² + y²)² = xy

Solution:

Given (x + y)² = 2axy

Now we have to find dy/dx of given equation, so by differentiating the equation on both sides with respect to x, we get,

9. Tan^-1 (x² + y²)

Solution:

Given tan ^{– 1}(x² + y²) = a,

Now we have to find dy/dx of given function, so by differentiating the equation on both sides with respect to x, we get,

Solution:

11. Sin xy + cos (x + y) = 1

Solution:

Given Sin x y + cos (x + y) = 1

Now we have to find dy/dx of given function, so by differentiating the equation on both sides with respect to x, we get,

Solution:

Solution:

Solution:

Solution: