RD Sharma Class 9 Solutions Chapter 7 VSAQs (Updated for 2024)

RD Sharma Class 9 Solutions Chapter 7 VSAQs

RD Sharma Class 9 Solutions Chapter 7 VSAQs: Clear all your basic doubts with the RD Sharma Solutions Class 9 Maths. You must know how to clear your Class 9 Maths exams with flying colours. RD Sharma Class 9 Solutions Chapter 7 VSAQs can make you stand out amongst your classmates. To know more, read the whole blog.

Access answers of RD Sharma Class 9 Solutions Chapter 7 VSAQs

Question 1.
Write the equation representing x-axis.
Solution:
The equation of x-axis is, y = 0.

Question 2.
Write the equation representing y-axis.
Solution:
The equation of y-axis is, x = 0.

 

Question 3.
Write the equation of a line passing through the point (0, 4) and parallel to x-axis.
Solution:
The equation of the line passing through the point (0,4) and parallel to x-axis will be y = 4.

Question 4.
Write the equation of a line passing through the point (3, 5) and parallel to x-axis.
Solution:
The equation of the line passing through the point (3, 5) and parallel to x-axis will be y = 5.

Question 5.
Write the equation of a line parallel toy-axis and passing through the point (-3, -7).
Solution:
The equations of the line passing through the point (-3, -7) and parallel to y-axis will be x = -3.

Question 6.
A line passes through the point (-4, 6) and is parallel to x-axis. Find its equation. A line passes through the point (-4, 6) and is parallel to x-axis. Find its equation.
Solution:
A line parallel to x-axis and passing through the point (-4, 6) will be y = 6.

Question 7.
Solve the equation 3x – 2 = 2x + 3 and represent the solution on the number line.
Solution:
3x – 2 = 2x + 3
⇒  3x – 2x = 3 + 2 (By terms formation)
⇒  x = 5
∴ x = 5
Solution on the number line is
RD Sharma Class 9 Solutions Chapter 7 Introduction to Euclid’s Geometry VSAQS Q7.1

Question 8.
Solve the equation 2y – 1 = y + 1 and represent it graphically on the coordinate plane.
RD Sharma Class 9 Solutions Chapter 7 Introduction to Euclid’s Geometry VSAQS Q8.1
Solution:
2y – 1 = y + 1
⇒ 2y – y = 1 +1
⇒  y = 2
∴ It is a line parallel to x-axis at a distance of 2 units above the x-axis is y = 2.

Question 9.
If the point (a, 2) lies on the graph of the linear equation 2x – 3y + 8 = 0, find the value of a.
Solution:
∵ 
Points (a, 2) lies on the equation
2x – 3y + 8 = 0
∴ It will satisfy the equation,
Now substituting the value of x = a, y = 2 in the equation
⇒ 2a – 3 x 2+ 8= 0
⇒ 2a + 2= 0
⇒ 2a = -2
⇒ a = 22 = -1
∴ a = -1

Question 10.
Find the value of k for which the point (1, -2) lies on the graph of the linear equation, x – 2y + k = 0.
Solution:
∵ Point (1, -2) lies on the graph of the equation x – 2y + k = 0
∴ x = 1, y = -2 will satisfy the equation
Now substituting the value of x = 1, y = -2 in it
1-2 (-2) + k = 0
⇒  1 + 4 + k = 0
⇒  5+ k = 0 ⇒  k =-5
∴  k = -5

This is the complete blog on RD Sharma Class 9 Solutions Chapter 7 VSAQs. To know more about the CBSE Class 9 Maths exam, ask in the comments.

FAQs on RD Sharma Class 9 Solutions Chapter 7 VSAQs

How many questions are there in RD Sharma for Class 9 Solutions Chapter 7 VSAQs?

There are 10 questions in RD Sharma Class 9 Solutions for Chapter 7 VSAQs.

Is it even beneficial to study RD Sharma for Class 9 Solutions Chapter 7 VSAQs?

Yes, your preparation will be strengthened with this amazing help book. All your questions will be answered by this book.

Are the solutions RD Sharma Class 9 Solutions Chapter 7 VSAQs relevant?

The solutions are relevant as they are designed by the subject matter experts.  

Leave a Comment

Top 10 Professional Courses With High-Paying Jobs 2024 Top 8 Online MCA Colleges in India 2024 Skills You Will Gain from an Online BBA Programme How to stay motivated during distance learning Things to know before starting with first year of medical school