RD Sharma Class 9 Solutions Chapter 3 VSAQS (Updated for 2024)

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Question 1.
Write the value of (2 + 3–√ ) (2 – 3–√).
Solution:
(2+ 3–√ )(2- 3–√ ) = (2)²-(3–√ )²
{∵ (a + b) (a – b) = a² – b²}
= 4-3=1

Question 2.
Write the reciprocal of 5 + 2–√.
Solution:

Question 3.
Write the rationalisation factor of 7 – 35–√ .
Solution:
Rationalising factor of 7 – 35–√ is 7 + 35–√
{∵ (a−−√ + b√  ) (a−−√ – b√) = a-b}

Question 4.

Solution:

Question 5.
If x =2–√ – 1 then write the value of 1x.
Solution:

Question 6.
If a = 2–√ + h then find the value of a –1a
Solution:

Question 7.
If x = 2 + 3–√, find the value of x + 1x.
Solution:

Question 8.
Write the rationalisation factor of 5–√ – 2.
Solution:
Rationalisation factor of 5–√ – 2 is 5–√ + 2 as
(a−−√ + b√)(a−−√ – b√) = a – b

Question 9.
Simplify : 3+22–√−−−−−−−√.
Solution:

Question 10.
Simplify : 3−22–√−−−−−−−√.
Solution:

Question 11.
If x = 3 + 2 2–√, then find the value of  x−−√ – 1x√.
Solution:

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