RD Sharma Class 9 Solutions Chapter 17 MCQS (2023)

RD Sharma Class 9 Solutions Chapter 17 MCQS

RD Sharma Class 9 Solutions Chapter 17 MCQs are available here. You can get the detailed PDFs for RD Sharma Class 9 Solutions Chapter 17 MCQs from the link provided below. These Solutions will be very beneficial for your class 9 exams.

RD Sharma Class 9 Maths Solutions

Table of Contents

Access RD Sharma Class 9 Solutions Chapter 17 MCQS

Question 1:

Mark the correct alternative in each of the following:

The sides of a triangle are 16 cm, 30 cm, 34 cm. Its area is

(a) 225 cm²

(b) 240 cm²

(c) $225 \sqrt{2}$ cm²

(d) 450 cm²

ANSWER:

The area of a triangle having sides a, b, c and s as semi-perimeter is given by,

, where

Therefore the area of a triangle say A, having sides 16 cm, 30 cm and 34 cm is given by

a = 16 cm ; b = 30 cm ; c = 34 cm

Therefore the area of the triangle is

Hence, the correct option is (b).

Question 2:

The base of an isosceles right triangle is 30 cm. Its area is

(a) 225 cm²

(b) 225 $\sqrt{3}$ cm²

(c) 225 $\sqrt{2}$ cm²

(d) 450 cm²

ANSWER:

$Let ABC be the right triangle in which ∠ B = 90 ° . Now, base = BC; perpendicular = AB; Hypotenuse = AC Now, BC = 30 cm (given) Now, ∆ ABC is an isosceles right angled ∆ and we know that hypotenuse is the longest side of the right ∆ . So, AB = BC = 30 cm area of ∆ ABC = \frac{1}{2} \times base \times height = \frac{1}{2} \times BC \times AB = \frac{1}{2} \times 30 \times 30 = 450 {cm}^{2}$ $Let ABC be the right triangle in which ∠ B = 90 ° . Now, base = BC; perpendicular = AB; Hypotenuse = AC Now, BC = 30 cm (given) Now, ∆ ABC is an isosceles right angled ∆ and we know that hypotenuse is the longest side of the right ∆ . So, AB = BC = 30 cm area of ∆ ABC = \frac{1}{2} \times base \times height = \frac{1}{2} \times BC \times AB = \frac{1}{2} \times 30 \times 30 = 450 {cm}^{2}$

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RD Sharma Class 9 Solutions Chapter 17 MCQS (Updated for 2024)