RD Sharma Class 10 Solutions Chapter 8 Quadratic Equations Exercise 8.5 (Updated for 2023)

RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5

RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5: In this exercise, the main focus is on another method known as the Quadratic formula. The Shreedharacharya’s rule is another name for it. This approach solves some of the drawbacks of factorization. Students can refer to the RD Sharma Solutions Class 10 prepared by experts at Kopykitab for a more in-depth study of this concept. Below you will get the RD Sharma Solutions for Class 10 Maths Chapter 8 Exercise 8.5 PDF.

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RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5

Access answers to RD Sharma Solutions Class 10 Maths Chapter 8 Exercise 8.5- Important Question with Answers

1. Write the discriminant of the following quadratic equations:

(i) 2x2 – 5x + 3 = 0

Solution:

Given equation,

2x2 – 5x + 3 = 0

It is in the form of ax2 + bx + c = 0

Where, a = 2, b = -5 and c = 3

So, the discriminant is given by D = b2 – 4ac

D = (-5)2 – 4 x 2 x 3

D = 25 – 24 = 1

Hence, the discriminant of the given quadratic equation is 1.

(ii) x2 + 2x + 4 = 0

Solution:

Given equation,

x2 + 2x + 4 = 0

It is in the form of ax2 + bx + c = 0

Where, a = 1, b = 2 and c = 4

So, the discriminant is given by D = b2 – 4ac

D = (2)2 – 4 x 1 x 4

D = 4 – 16 = – 12

Hence, the discriminant of the given quadratic equation is – 12.

(iii) (x – 1)(2x – 1) = 0

Solution:

Given equation,

(x -1) (2x -1) = 0

On expanding it, we get

2x2 – 3x + 1 = 0

It is in the form of ax2 + bx + c = 0

Where, a = 2, b = -3, c = 1

So, the discriminant is given by D = b2 – 4ac

D = (-3)2 – 4 x 2 x 1

D = 9 – 8 = 1

Hence, the discriminant of the given quadratic equation is 1.

(iv) x2 -2x + k = 0, k ∈ R

Solution:

Given equation,

x– 2x + k = 0

It is in the form of ax2 + bx + c = 0

Where, a = 1, b = -2, and c = k

So, the discriminant is given by D = b2 – 4ac

D = (-2)2 – 4(1)(k)

= 4 – 4k

Hence, the discriminant of the given equation is (4 – 4k).

R D Sharma Solutions For Class 10 Maths Chapter 8 Quadratic Equations ex 8.5 - 1

(vi) x2 – x + 1 = 0

Solution:

Given equation,

x2 – x + 1 = 0 It is in the form of ax2 + bx + c = 0

Where, a = 1, b = -1 and c = 1

So, the discriminant is given by D = b2 – 4ac

D = (-1)2 – 4 × 1 × 1

D = 1 – 4 = – 3

Thus, the discriminant of the given equation is -3.

We have provided complete details of RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5. If you have any queries related to CBSE Class 10, feel free to ask us in the comment section below.

FAQs on RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5

How is RD Sharma Class 10 Solutions Chapter 8 Exercise 8.5 helpful for board exams?

For self-evaluation, RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 provides solutions with thorough descriptions as per term limits specified by the Board. Students will gain valuable experience solving these problems, allowing them to complete the assignment on time.

Is the RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 available on the Kopykitab website?

Yes, the PDFs of RD Sharma Class 10 Maths Solutions Chapter 8 Exercise 8.5 are available. These solutions are created in a unique method by Kopykitab’s expert faculty.

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