RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4 (Updated for 2024)

RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4

RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4: This exercise delves deeper into the basic proportionality theorem. A few problems are solved in the proper manner to reinforce the fundamental principle. Students can use the RD Sharma Class 10 Solutions to learn how to present and make their solutions error-free. Students who want to get good grades in Class 10 Maths Chapter 4 Exercise 4.4 can download the RD Sharma Solutions for Class 10 Maths Chapter 4 Exercise 4.4 PDF.

Download RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4 Free PDF

 


RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4

Access answers to RD Sharma Solutions Class 10 Maths Chapter 4 Exercise 4.4- Important Question with Answers

1. (i) In fig. 4.70, if AB∥CD, find the value of x.

Solution:

It’s given that AB∥CD.

Required to find the value of x.

C:\Users\Tnluser\Downloads\extra-images-of-RD-Sharma-Chapter-4--ex-4.4-3.png

We know that,

Diagonals of a parallelogram bisect each other.

So,

AO/ CO = BO/ DO

⇒ 4/ (4x – 2) = (x +1)/ (2x + 4)

4(2x + 4) = (4x – 2)(x +1)

8x + 16 = x(4x – 2) + 1(4x – 2)

8x + 16 = 4x2 – 2x + 4x – 2

-4x2 + 8x + 16 + 2 – 2x = 0

-4x+ 6x + 8 = 0

4x2 – 6x – 18 = 0

4x2 – 12x + 6x – 18 = 0

4x(x – 3) + 6(x – 3) = 0

(4x + 6) (x – 3) = 0

∴ x = – 6/4 or x = 3

(ii)  In fig. 4.71, if AB∥CD, find the value of x.

Solution:

It’s given that AB∥CD.

Required to find the value of x.

C:\Users\Tnluser\Downloads\extra-images-of-RD-Sharma-Chapter-4--ex-4.4-1.png

We know that,

Diagonals of a parallelogram bisect each other

So,

AO/ CO = BO/ DO

⇒ (6x – 5)/ (2x + 1) = (5x – 3)/ (3x – 1)

(6x – 5)(3x – 1) = (2x + 1)(5x – 3)

3x(6x – 5) – 1(6x – 5) = 2x(5x – 3) + 1(5x – 3)

18x2 – 10x2 – 21x + 5 + x +3 = 0

8x2 – 16x – 4x + 8 = 0

8x(x – 2) – 4(x – 2) = 0

(8x – 4)(x – 2) = 0

x = 4/8 = 1/2 or x = -2

∴ x= 1/2

(iii) In fig. 4.72, if AB ∥ CD. If OA = 3x – 19, OB = x – 4, OC = x- 3 and OD = 4, find x.

Solution:

It’s given that AB∥CD.

Required to find the value of x.

C:\Users\Tnluser\Downloads\extra-images-of-RD-Sharma-Chapter-4--ex-4.4-2.png

We know that,

Diagonals of a parallelogram bisect each other

So,

AO/ CO = BO/ DO

(3x – 19)/ (x – 3) = (x–4)/ 4

4(3x – 19) = (x – 3) (x – 4)

12x – 76 = x(x – 4) -3(x – 4)

12x – 76 = x2 – 4x – 3x + 12

-x2 + 7x – 12 + 12x -76 = 0

-x+ 19x – 88 = 0

x– 19x + 88 = 0

x2 – 11x – 8x + 88 = 0

x(x – 11) – 8(x – 11) = 0

∴ x = 11 or x = 8


We have provided complete details of RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4. If you have any queries related to CBSE Class 10, feel free to ask us in the comment section below.

FAQs on RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4

Is it important to study all of the concepts included in RD Sharma Class 10 Solutions Chapter 4 Exercise 4.4?

Yes, learning all of the concepts included in RD Sharma Solutions for Class 10 Maths Chapter 4 Exercise 4.4 is required in order to achieve high scores on the Class 10 board exams. These solutions were created by subject matter specialists who compiled model questions that covered all of the textbook’s exercise questions.

Where can I download RD Sharma Class 10 Maths Solutions Chapter 4 Exercise 4.4 free PDF?

You can download RD Sharma Class 10 Maths Solutions Chapter 4 Exercise 4.4 free PDF from the above article.

What are the benefits of using RD Sharma Class 10 Maths Solutions Chapter 4 Exercise 4.4?

1. Correct answers according to the latest CBSE guidelines and syllabus.
2. The RD Sharma Class 10 Maths Solutions Chapter 4 Exercise 4.4 is written in simple language to assist students in their board examination, & competitive examination preparation.

Leave a Comment

Top 10 Professional Courses With High-Paying Jobs 2024 Top 8 Online MCA Colleges in India 2024 Skills You Will Gain from an Online BBA Programme How to stay motivated during distance learning Things to know before starting with first year of medical school