RD Sharma Chapter 17 Class 9 Maths Exercise 17.1 Solutions

RD Sharma Chapter 17 Class 9 Maths Exercise 17.1 Solutions is based on the Construction of Bisector of a Line Segment. This exercise is going to address the fundamental aspects concerned with Constructions. The complete range of questions is addressed through the best assist of figures, making it easy to understand. It provides details for the students to understand how to draw bisector in perpendicular form for a section of the line. Upon practicing these questions, one can easily solve questions based on constructing the bisector of a line segment. As the details are provided in a step-by-step procedure, which helps students to understand more conveniently.

The attached PDF below will help students solve the questions more efficiently as we have given a step-by-step explanation of the solution with relevant examples. The RD Sharma Chapter 17 Class 9 Maths Exercise 17.1 Solutions PDF is available for free for the learners to practice and score well in the exam.

Learn about RD Sharma Chapter 17 (Constructions) Class 9

Download RD Sharma Chapter 17 Class 9 Maths Exercise 17.1 Solutions PDF

Solutions for Class 9 Maths Chapter 17 Construction Exercise 17.1

Important Definition RD Sharma Chapter 17 Class 9 Maths Exercise 17.1 Solutions

Here is the step to the Construction of Bisector of a Line Segment and Right Angle using a compass (protractor) and a straightedge.

1. Put the compass at one edge of a line segment.
2. Adjust the device (compass) to slightly longer than half a line segment length.
3. Draw arcs over and beneath the line.
4. Holding the same compass width, draw arcs from another edge of a line.
5. Place ruler wherever the arcs intersect and draw a line segment.

Examples of Bisector of Line Segment of RD Sharma Chapter 17 Class 9 Maths Exercise 17.1 Solutions

Look at the following examples, which have a step-wise solution to construct a bisector. These few examples help to understand the question of this exercise. For more practice, download the above PDF.

Ques: Draw a line section of length 8.6 cm. Divide it and measure the length of each part.

Solution-

1. Draw a line section XY = 8.6 cm.
2. Draw arcs on every side of XY using X as a center at any radius more than half of 8.6.
3. Repeat Step 2 using Y as a center and make sure these arcs cut the previous arcs.
4. Join the P and Q points, which meets XY at M. Therefore, XM= MY = 4.3 cm.

Ques: Draw a line section XY of length 5.8cm. Draw the perpendicular bisector of this line section.

Solution-

1. Draw a line section XY = 5.8 cm.
2. Draw arcs on every side of XY using X as a center at any radius more than half of 5.8.
3. Repeat Step 2 using Y as a center and make sure these arcs cut the previous arcs.
4. Join the points A and B.

Here, AB is the perpendicular bisector of XY.

Ques: Draw a circle with center at point O and radius 5cm. Draw its chord XY, the perpendicular bisector of line section XY. Does it pass within the center of the circle?

Solution-

1. Draw a circle taking a radius of 5 cm and point O as center.
2. Draw a chord XY using the scale.
3. Draw arcs one on each edge of the chord, choosing X as center and radius more than half of 5 cm.
4. Repeat step 3 using B as a center and make sure these arcs cut the previous arcs.
5. Join A and B.

Therefore AB is a perpendicular bisector of chord XY that passes within the center of the circle.

Frequently Asked Question (FAQs) of RD Sharma Chapter 17 Class 9 Maths Exercise 17.1 Solution

Ques- What does construction here basically mean?

Ans- Construction in geometry primarily means making angles, lines, and different other types of shapes with perfection. And, all that a student can use for this is a ruler and a compass.

Ques- Is the Construction topic important for those aspiring to higher studies in Mathematics?

Ans- Yes, the Construction topic is as important as other chapters. In fact, the entire geometry as a subject is crucial for those aspiring for higher studies in Mathematics.

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