RS Aggarwal Solutions Class 8 Maths Chapter 8 Linear Equations (Updated For 2024)

RS Aggarwal Solutions Class 8 Maths Chapter 8 Linear Equations: Subject matter experts have designed accurate and well-explained solutions for RS Aggarwal Solutions Class 8 Maths. You can rely on the solutions of RS Aggarwal Solutions Class 8 Maths Chapter 8 Linear Equations and they are easy to understand as well. Ace your Class 8 Maths exam with this amazing guidebook.

Download the Free PDF of RS Aggarwal Solutions Class 8 Maths Chapter 8 Linear Equations with the link given in the blog. To know more, read the whole blog.

Download RS Aggarwal Solutions Class 8 Maths Chapter 8 Linear Equations PDF

RS Aggarwal Solutions Class 8 Maths Chapter 8 Linear Equations

Access The RS Aggarwal Solutions Class 8 Maths Chapter 8 Linear Equations

Question 1.

Solve:

8x + 3 = 27 + 2x

Answer:

8x + 3 = 27 + 2x

By transposition,

⇒ 8x – 2x = 27 − 3

⇒ 6x = 24

⇒ x = 4

Question 2.

Solve:

5x + 7 = 2x – 8

Answer:

5x + 7 = 2x – 8

 

By transposition,

 

⇒ 5x−2x = – 8 – 7

 

⇒ 3x = – 15

 

⇒ x = – 5

Question 3.

Solve:

2z – 1 = 14 – z

Answer:

2z – 1 = 14 – z

 

By transposition,

 

⇒ 2z + z = 14 + 1

 

⇒ 3z = 15

Dividing by 3, on both the sides we get,

⇒ z = 5

Question 4.

Solve:

9x + 5 = 4(x – 2) + 8

Answer:

9x + 5 = 4(x – 2) + 8

 

By transposition,

 

⇒ 9x + 5 = 4x – 8 + 8

 

⇒ 9x – 4x = – 5 + 0

 

⇒ 5x = – 5

 

⇒ x = – 1

Question 5.

Solve:

Answer:

 

By cross multiplication

 

_⇒

 

Taking LCM of 5 and 1 = 5 on LHS

 

 

⇒ 2y = – 5 × 4

 

⇒ y = – 5 × 2 = – 10

Question 6.

Solve:

3x +  = 2x + 1

Answer:

3x +  = 2x + 1

 

By cross multiplication

 

 

Taking LCM of 3 and 1 = 3 on RHS

 

Question 7.

Solve:

15(y – 4) – 2(y – 9) + 5(y + 6) = 0

Answer:

15(y – 4) – 2(y – 9) + 5(y + 6) = 0

Opening the brackets and multiplying, we get,

⇒ 15y – 60 – 2y + 18 + 5y + 30 = 0

⇒ 15y – 2y + 5y – 60 + 18 + 30 = 0

⇒ 18y = 12

Question 8.

Solve:

3(5x – 7) – 2(9x – 11) = 4(8x – 13) – 17

Answer:

3(5x – 7) – 2(9x – 11) = 4(8x – 13) – 17

Multiplying we get,

⇒ 15x – 21 – 18x + 22 = 32x – 52 – 17

Solving, we get
(15x – 18x) + (22 – 21) = 32x – (52 + 17)

⇒ – 3x + 1 = 32x – 69

⇒ 35x = 70

⇒ x = 2

RS Aggarwal Solutions Class 8 Maths for Chapter 8 Linear Equations – Overview

RS Aggarwal Solutions Class 8 Maths for Chapter 8 will make you familiar with the concept of real and rational numbers. A real number can be represented on the real number line. However, it is the same with rational numbers. Hence, some numbers are not rational, but we can still represent them on a number line. That’s why, all the rational numbers are real numbers, but all the real numbers might not be rational. 

In the RS Aggarwal Solutions Class 8 Maths for Chapter 8 Linear Equations, Ex 8.1, you will understand the concept more clearly and you can solve all the questions of Linear Equations with ease.

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