RD Sharma Class 9 Solutions Chapter 17 Exercise 17.2 (Updated for 2023)

RD Sharma Class 9 Solutions Chapter 17 Exercise 17.2: This exercise is based on the construction of the bisector of a given angle. The questions are also according to the syllabus and guidelines of CCE and the Central Board of Secondary Education. Exercise 17.2 of RD Sharma Class 9 Chapter 17 helps students to learn how to construct different angles with the help of a ruler and a compass only.

You can get the PDF of RD Sharma Class 9 Solutions Chapter 17 Exercise 17.2 for free. These solutions are created in detail by our experts. You can get a free PDF from the link provided below.

• RD Sharma Class 9 Maths Solutions

Download RD Sharma Class 9 Solutions Chapter 17 Exercise 17.2

RD Sharma Class 9 Solutions Chapter 17 Exercise 17.2

Access RD Sharma Class 9 Solutions Chapter 17 Exercise 17.2

 Draw an angle and label it as ∠BAC. Construct another angle, equal to ∠BAC.

Solution:

Steps of construction:

Step 1: Draw any angle ABC.

Now will construct an angle equal to ∠BAC

Step 2: Draw a line segment QR.

Step 3: Draw an arc that intersects ∠BAC at E and D using A as a center and choose any radius.

Step 4: With the same measurements (set in step 2), Draw an arc from point Q.

Step 5: With S as the center and radius equal to DE, draw an arc that intersects the previous arc at T.

Step 6: Join Q and T.

Therefore ∠PQR= ∠BAC

Question 2: Draw an obtuse angle. Bisect it. Measure each of the angles so formed.

Solution:

Steps of construction:

Step 1: Draw an obtuse angle. We choose ∠ABC = 120⁰.

Step 2: Draw an arc that intersects AB at P and BC at Q, from center B and choose any radius.

Step 3: Draw an arc from point P by setting a radius of more than half of PQ.

Step 4: Repeat step 3 using Q as a center and cut the previous arc at R.

Step 5: Join BR.

Therefore ∠ABR= ∠RBC = 60⁰

Question 3: Using your protractor, draw an angle of 108⁰. With this given angle as given, draw an angle of 54⁰.

Solution:

Steps of construction:

Step 1: Draw ∠ABC = 108⁰.

Step 2: Draw an arc that intersects AB at P and BC at Q from point B. (Choose any radius)

Step 3: Draw an arc from point P by setting a radius of more than half of PQ.

Step 4: Repeat Step 3 using Q as the center and intersect the previous arc at R.

Step 5: Join BR.

Therefore ∠RBC = 54⁰

Question 4: Using the protractor, draw a right angle. Bisect it to get an angle of measure 45⁰.

Solution:

Steps of construction:

Step 1: Draw ∠ABC = 90⁰.

Step 2: Draw an arc that intersects AB at P and BC at Q from point B. (Choose any radius)

Step 3: Draw an arc from point P by setting a radius of more than half of PQ.

Step 4: Repeat step 3 using Q as a center and intersect the previous arc at R.

Step 5: Join RB.

Therefore ∠RBC= 45⁰

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